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3.63 for a turbine designed with an optimum tip speed ratio of 7. As an example, assume that this turbine is stall regulated and operates at a fixed rotational speed at a site where the average wind speed is 6 m/s and the Weibull shape factor k = 1.8, then, from Eq. (2.2), the scale factor c = 6.75 m/s.

      The required maximum electrical power of the machine is 500 kW, the transmission loss is 10 kW, the mean generator efficiency is 90%, and the availability of the turbine (amount of time for which it is available to operate when maintenance and repair time is taken into account) is 98%.

Graph depicts the C P -λ curve for a design tip speed ratio of 7 at 7 m/s. Graph depicts the K P -1/λ curve for a fixed-speed, stall-regulated turbine.

      The maximum rotor shaft power (aerodynamic power) is then

      (3.97)normal upper P Subscript normal s Baseline equals left-parenthesis 500 plus 10 right-parenthesis slash 0.9 equals 567 k upper W

      The wind speed at which maximum power is developed (where dCP/dλ = 3CP/λ for fixed speed) is 13 m/s, therefore the rotor swept area must be, assuming an air density of 1.225 kg/m3,

567 000 slash left-parenthesis 1 slash 2 times 1.225 times 13 cubed times 0.22 right-parenthesis equals 1.92 times 10 cubed normal m squared

      The rotor radius is therefore 24.6 m.

48.1 slash 24.6 r a d slash normal s equals 1.96 r a d slash normal s comma which is 1.96 times 60 slash 2 pi r e v slash min equals 18.7 r e v slash min period

      The power vs wind speed curve for the turbine can then be obtained from Figure 3.64.

      (3.98)StartLayout 1st Row 1st Column Blank 2nd Column Power left-parenthesis electrical right-parenthesis 2nd Row 1st Column Blank 2nd Column equals left-parenthesis upper K Subscript upper P Baseline times italic one half times italic 1.225 italic k g slash m cubed times left-parenthesis italic 48 period italic 1 m slash s right-parenthesis cubed times italic 1.92 times italic 10 cubed m squared minus italic 10 times italic 1000 upper W right-parenthesis times italic 0.9 EndLayout

      To determine the energy capture of the turbine over a time period T, the product of the power characteristic P(u) with the probability f(u) is integrated with respect to time over T. This can be converted to an integral with respect to wind speed u over the wind speed range, since f(u) is the proportion of time T spent at wind speed u, and therefore:

      (3.99)f left-parenthesis u right-parenthesis period delta u equals StartFraction delta upper T Over upper T EndFraction

      with

      (3.100)integral Subscript 0 Superscript infinity Baseline f left-parenthesis u right-parenthesis period italic d u equals 1

      The operational speed range will be between the cut‐in speed and the cut‐out speed. The cut‐in speed is determined by the transmission losses: at what wind speed does the turbine begin to generate power? The cut‐in speed is usually chosen to be somewhat higher than the zero power speed, in the present case, say 4 m/s.

Graph depicts the power versus wind speed.

      The total energy captured (E) by the turbine in a time period T is

      (3.101)upper T integral Subscript StartFraction upper U Subscript italic c i Baseline Over upper U overbar EndFraction Superscript StartFraction upper U Subscript italic c o Baseline Over upper U overbar EndFraction Baseline upper P left-parenthesis u right-parenthesis f left-parenthesis u right-parenthesis italic d u equals upper E

      which is the area under the curve of Figure 3.66 times the time T. Unfortunately, the integral does not have a closed mathematical form in general, and so a numerical integration is required, such as the trapezoidal rule or, for better accuracy, Simpson's rule.

      (3.102)upper E equals 4.5413 dot 10 Superscript 8 Baseline italic k upper W h

Graph depicts the energy capture curve. Graph depicts the energy capture curve for numerical integration. Graph depicts the energy capture curve for variable-speed turbine.

      The

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