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It is expressed through Dirac's delta function as images. The lumped line constants R, L, C, G are given for p.u.l.

      The loop and node equations are written below to develop the Kelvin–Heaviside transmission line equations with a current source:

      The Loop Equation

equation

      The Node Equation

equation

      For Δx → 0, the above equations are reduced to

      (2.1.52)equation

      The above equations are rewritten below in term of the characteristic impedance (Z0) and propagation constant (γ) of a transmission line:

      (2.1.53)equation

      On solving the above equations for the voltage, the following inhomogeneous voltage wave equation, with a current source, is obtained:

      

      2.1.7 Solution of Voltage and Current‐Wave Equation

      The voltage and current wave equations in the phasor form are given in equation (2.1.37). The solution of a wave equation is written either in terms of the hyperbolic functions or in terms of the exponential functions. The first form is suitable for a line terminated in an arbitrary load. A section of the line transforms the load impedance into the input impedance at any location on the line. The impedance transformation takes place due to the standing wave formation. The hyperbolic form of the solution also provides the voltage and current distributions along the line. The exponential form of the solution demonstrates the traveling waves on a line, both in the forward and in the backward directions. A combination of the forward‐moving and the backward‐moving waves produces the standing wave on a transmission line.

      The Hyperbolic Form of a Solution

Schematic illustration of transmission line circuit. The distance x is measured from the source end; whereas the distance d is measured from the load.

      (2.1.57)equation

      The phasor line voltage and line current are written as follows:

      The constants A1 and B1 are determined by using the boundary conditions at input x = 0 and output x = ℓ.

       At x = 0, the line input voltage is , giving the value of A1:(2.1.59)

      At the receiving end, x = ℓ, the load end voltage and current are