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relates s and t in the following way:

equation

      Setting the spherical aberration to zero and substituting for t we have the following expression given entirely in terms of s:

equation equation equation

      Finally this gives the solution for s as:

      Accordingly the solution for t is

      (4.39b)equation

      Of course, since the equation for spherical aberration gives quadratic terms in s and t, it is not surprising that two solutions exist. Furthermore, it is important to recognise that the sign of t is the opposite to that of s. Referring to Figure 4.10, it is clear that the form of the lens is that of a meniscus. The two solutions for s correspond to a meniscus lens that has been inverted. Of course, the same applies to the conjugate parameter, so, in effect, the two solutions are identical, except the whole system has been inverted, swapping the object for image and vice-versa.

equation

      As previously set out, the increase in numerical aperture of an aplanatic meniscus lens is equal to minus the ratio of the object and image distances. Therefore, the aplanatic meniscus lens increases the system power by a factor equal to the refractive index of the lens. This principle is of practical consequence in many system designs. Of course, if we reverse the sense of Figure 4.14 and substitute the image for the object and vice versa, then the numerical aperture is effectively reduced by a factor of n.

Geometrical illustration of a meniscus lens with positive focal power.

      Worked Example 4.4 Microscope Objective – Hyperhemisphere Plus Meniscus Lens

      What are the radii of curvature of the meniscus lens and what is the location of the (virtual) image for the combined system? The system is as illustrated below.

Geometrical illustration of an extra meniscus lens situated at the vertex of the hyperhemisphere with a negligible separation and the meniscus lens in the aplanatic arrangement. equation

      There remains the question of the choice of the sign for the conjugate parameter. If one refers to Figure 4.14, it is clear that the sense of the object and image location is reversed. In this case, therefore, the value of t is equal to +4.33 and the numerical aperture of the system is reduced by a factor of 1.6 (the refractive index). In that case, the image distance must be equal to minus 1.6 times the object distance. That is to say:

equation

      We can calculate the focal length of the lens from:

equation

      Therefore the focal length of the meniscus lens is 62.4 mm. If the conjugate parameter is +4.33, then the shape factor must be −(2n + 1), or −4.2 (note the sign). It is a simple matter to calculate the radii of the two surfaces from Eq. (4.29):

equation equation

      Finally, this gives R1 as −23.4 mm and R2 as −14.4 mm. The signs should be noted. This follows the convention that positive displacement follows the direction from object to image space.

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