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the value answer will be set to something before it is used. The otherAnswer variable is not initialized but never used, and the compiler is equally as happy. Remember, the compiler is only concerned if you try to use uninitialized local variables; it doesn't mind the ones you never use.

      The onlyOneBranch variable is initialized only if check happens to be true. The compiler knows there is the possibility for check to be false, resulting in uninitialized code, and gives a compiler error. You learn more about the if statement in Chapter 3, “Making Decisions.”

       On the exam, be wary of any local variable that is declared but not initialized in a single line. This is a common place on the exam that could result in a “Does not compile” answer. Be sure to check to make sure it's initialized before it's used on the exam.

      Passing Constructor and Method Parameters

      Variables passed to a constructor or method are called constructor parameters or method parameters, respectively. These parameters are like local variables that have been pre-initialized. The rules for initializing constructor and method parameters are the same, so we focus primarily on method parameters.

      In the previous example, check is a method parameter.

      public void findAnswer(boolean check) {}

      Take a look at the following method checkAnswer() in the same class:

      public void checkAnswer() { boolean value; findAnswer(value); // DOES NOT COMPILE }

      The call to findAnswer() does not compile because it tries to use a variable that is not initialized. While the caller of a method checkAnswer() needs to be concerned about the variable being initialized, once inside the method findAnswer(), we can assume the local variable has been initialized to some value.

      Defining Instance and Class Variables

      Variables that are not local variables are defined either as instance variables or as class variables. An instance variable, often called a field, is a value defined within a specific instance of an object. Let's say we have a Person class with an instance variable name of type String. Each instance of the class would have its own value for name, such as Elysia or Sarah. Two instances could have the same value for name, but changing the value for one does not modify the other.

      On the other hand, a class variable is one that is defined on the class level and shared among all instances of the class. It can even be publicly accessible to classes outside the class and doesn't require an instance to use. In our previous Person example, a shared class variable could be used to represent the list of people at the zoo today. You can tell a variable is a class variable because it has the keyword static before it. You learn about this in Chapter 5. For now, just know that a variable is a class variable if it has the static keyword in its declaration.

      Instance and class variables do not require you to initialize them. As soon as you declare these variables, they are given a default value. The compiler doesn't know what value to use and so wants the simplest value it can give the type: null for an object, zero for the numeric types, and false for a boolean. You don't need to know the default value for char, but in case you are curious, it is '\u0000' (NUL).

      Inferring the Type with var

      You have the option of using the keyword var instead of the type when declaring local variables under certain conditions. To use this feature, you just type var instead of the primitive or reference type. Here's an example:

      public class Zoo { public void whatTypeAmI() { var name = "Hello"; var size = 7; } }

      The formal name of this feature is local variable type inference. Let's take that apart. First comes local variable. This means just what it sounds like. You can only use this feature for local variables. The exam may try to trick you with code like this:

      public class VarKeyword { var tricky = "Hello"; // DOES NOT COMPILE }

Wait a minute! We just learned the difference between instance and local variables. The variable tricky is an instance variable. Local variable type inference works with local variables and not instance variables.

      Type Inference of var

      Now that you understand the local variable part, it is time to go on to what type inference means. The good news is that this also means what it sounds like. When you type var, you are instructing the compiler to determine the type for you. The compiler looks at the code on the line of the declaration and uses it to infer the type. Take a look at this example:

      7: public void reassignment() { 8: var number = 7; 9: number = 4; 10: number = "five"; // DOES NOT COMPILE 11: }

      On line 8, the compiler determines that we want an int variable. On line 9, we have no trouble assigning a different int to it. On line 10, Java has a problem. We've asked it to assign a String to an int variable. This is not allowed. It is equivalent to typing this:

      int number = "five";

       If you know a language like JavaScript, you might be expecting var to mean a variable that can take on any type at runtime. In Java, var is still a specific type defined at compile time. It does not change type at runtime.

      For simplicity when discussing var, we are going to assume a variable declaration statement is completed in a single line. You could insert a line break between the variable name and its initialization value, as in the following example:

      7: public void breakingDeclaration() { 8: var silly 9: = 1; 10: }

      This example is valid and does compile, but we consider the declaration and initialization of silly to be happening on the same line.

      Examples with var

      Let's go through some more scenarios so the exam doesn't trick you on this topic! Do you think the following compiles?

3: public void doesThisCompile(boolean check) { 4: var question; 5: question = 1; 6: var answer; 7: if (check) { 8: answer = 2; 9: } else { 10: answer = 3; 11: } 12: System.out.println(answer); 13: }

      The code does not compile. Remember that for local variable type inference, the compiler looks only at the line with the declaration. Since question and answer are not assigned values on the lines where they are defined, the compiler does not know what to make of them. For this reason, both lines 4 and 6 do not compile.

      You might find that strange since both branches of the if/else do assign a value. Alas, it is not on the same line as the declaration, so it does not count for var. Contrast this behavior with what we saw a short while ago when we discussed branching and initializing a local variable in our findAnswer() method.

      Now we know the initial value used to determine the type needs to be part of the same statement. Can you figure out why these two statements don't compile?

      4: public void

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