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0.8962 0.8980 0.8997 0.9015 ⋮
p1510202550
pth percentile−2.33−1.645−1.28−0.84−0.670.00
p758090959999.9
pth percentile0.670.841.281.6452.333.09

      When X is a normal distribution with μ≠0 or σ≠1, the distribution of X is called a non-standard normal distribution. The standard normal distribution is the reference distribution for all normal distributions because all of the probabilities and percentiles for a non-standard normal can be determined from the standard normal distribution. In particular, the following relationships between a non-standard normal with mean µ and standard deviation σ and the standard normal can be used to convert a non-standard normal value to a Z-value and vice versa.

       THE RELATIONSHIPS BETWEEN A STANDARD NORMAL AND A NON-STANDARD NORMAL

      1 If X is a non-standard normal with mean µ and standard deviation σ, then Z=(X−μ)/σ.

      2 If Z is a standard normal, then X=σ⋅Z+μ is a non-standard normal with mean µ and standard deviation σ.

      Figure 2.29 The correspondence between the values of a standard normal and a non-standard normal.

      To determine the cumulative probability for the value of a non-standard normal, say x, convert the value of x to its corresponding z value using z=z−μ/σ; then determine the cumulative probability for this z value. That is,

upper P left-parenthesis upper X less-than-or-equal-to x right-parenthesis equals upper P left-parenthesis upper Z less-than-or-equal-to StartFraction x minus mu Over sigma EndFraction right-parenthesis

       NON-STANDARD NORMAL PROBABILITIES

      If X is a non-standard normal variable with mean µ and standard deviation σ, then

      1 P(X≥x)=1−P(X≤x) =1−P(Z≤x−μσ)

      2 P(a≤X≤b)=P(X≤b)−P(X≤b) =P(Z≤b−μσ)−P(Z≤a−μσ)

      Note that each of the probabilities associated with a non-standard normal distribution is based on the process of converting an x value to a z value using the formula Z=(x−μ)/σ. The reason why the standard normal can be used for computing every probability concerning a non-standard normal is that there is a one-to-one correspondence between the Z and X values (see Figure 2.29).

       Example 2.38

      Figure 2.30 P(700≤X≤1000).

      Figure 2.31 The Z region corresponding to 700≤X≤1000.

       Example 2.39

      The distribution of IQ scores is approximately normal with µ = 100 and σ = 15. Using this normal distribution to model the distribution of IQ scores,

      1 an IQ score of 112 corresponds to a Z-value of

      2 the probability of having an IQ score of 112 or less is

      3 the probability of having an IQ score between 90 and 120 is

      4 the probability of having an IQ score of 150 or higher is

      The distribution of peak particle was reported to be approximately normal with mean particle size µ = 262 Å and standard deviation σ = 4 Å. Based on this study, the probability that a child or adolescent will have a peak particle size of less than 255 Å is

upper P left-parenthesis upper X less-than-or-equal-to 255 right-parenthesis equals upper P left-parenthesis StartFraction 255 minus 262 Over 4 EndFraction right-parenthesis equals upper P left-parenthesis upper Z less-than-or-equal-to negative 1.75 right-parenthesis equals 0.0401

      Thus, there is only a 4% chance that a child or adolescent will have peak particle size less than 255 Å.

      2.4.3 Z Scores

      The result of converting a non-standard normal value, a raw value, to a Z-value is a Z score. A Z score is a measure of the relative position a value has within its distribution. In particular, a Z score simply measures how many standard deviations a point is above or below the mean. When a Z score is negative the raw value lies below the mean of its distribution, and when a Z score is positive the raw value lies

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